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5-12i-5-12i-5-12i-5-12i-




Question Number 19433 by Tinkutara last updated on 11/Aug/17
(((√(5 + 12i)) + (√(5 − 12i)))/( (√(5 + 12i)) − (√(5 − 12i)))) =
$$\frac{\sqrt{\mathrm{5}\:+\:\mathrm{12}{i}}\:+\:\sqrt{\mathrm{5}\:−\:\mathrm{12}{i}}}{\:\sqrt{\mathrm{5}\:+\:\mathrm{12}{i}}\:−\:\sqrt{\mathrm{5}\:−\:\mathrm{12}{i}}}\:= \\ $$
Answered by ajfour last updated on 11/Aug/17
=((((√(5+12i))+(√(5−12i)))^2 )/(24i))  =((10+2(√(25+144)))/(24i))=(3/(2i))=−(3/2)i .
$$=\frac{\left(\sqrt{\mathrm{5}+\mathrm{12i}}+\sqrt{\mathrm{5}−\mathrm{12i}}\right)^{\mathrm{2}} }{\mathrm{24i}} \\ $$$$=\frac{\mathrm{10}+\mathrm{2}\sqrt{\mathrm{25}+\mathrm{144}}}{\mathrm{24i}}=\frac{\mathrm{3}}{\mathrm{2i}}=−\frac{\mathrm{3}}{\mathrm{2}}\mathrm{i}\:. \\ $$
Commented by Tinkutara last updated on 11/Aug/17
Thank you very much Sir!
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$

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