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5-2x-1-25-x-1-100-find-value-of-3-3-x-




Question Number 59730 by muneshkumar last updated on 14/May/19
5^(2x−1 ) =25^(x−1) +100 find value of 3^(3−x)
52x1=25x1+100findvalueof33x
Answered by tanmay last updated on 14/May/19
(5^(2x) /5)=(5^2 )^(x−1) +100  (((5^x )^2 )/5)=(5^(2x) /5^2 )+100  5^x =a  (a^2 /5)=(a^2 /(25))+100  (a^2 /5)−(a^2 /(25))=100  ((5a^2 −a^2 )/(25))=100  4a^2 =100×25  a^2 =(((10×5)/2))^2 =5^4   5^(2x) =5^4   2x=4  x=2  so  3^(3−2)   3^(3−2)   3^1   3
52x5=(52)x1+100(5x)25=52x52+1005x=aa25=a225+100a25a225=1005a2a225=1004a2=100×25a2=(10×52)2=5452x=542x=4x=2so332332313

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