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5-x-1-x-4-dx-




Question Number 84126 by Roland Mbunwe last updated on 09/Mar/20
∫((5−x)/(1+(√((x−4)))))dx
5x1+(x4)dx
Answered by MJS last updated on 09/Mar/20
−∫((x−5)/(1+(√(x−4))))dx=∫(1−(√(x−4)))dx=  =x−(2/3)(x−4)^(3/2) +C
x51+x4dx=(1x4)dx==x23(x4)32+C
Commented by MJS last updated on 09/Mar/20
−((x−5)/(1+(√(x−4))))×((1−(√(x−4)))/(1−(√(x−4))))=−(((x−5)(1−(√(x−4))))/(5−x))=  =1−(√(x−4))
x51+x4×1x41x4=(x5)(1x4)5x==1x4

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