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5-x-2-594-5-5-x-3-594-x-3-log-5-5-log-5-594-x-3-log-5-594-x-log-5-594-3-




Question Number 124819 by Ndala last updated on 06/Dec/20
5^(x+2) =((594)/5)  5^(x+3) =594  (x+3)log _5 5=log _5 594  x+3=log _5 594→x=log _5 594−3
5x+2=59455x+3=594(x+3)log55=log5594x+3=log5594x=log55943
Commented by $@y@m last updated on 06/Dec/20
Please use editor option (available  under ≡) for rough work.
Pleaseuseeditoroption(availableunder)forroughwork.

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