5-x-4-x-3-x-2-x-1-x-x-1-x-2-x-3-x-4-x-5-2-gt-1-15-za-

Question Number 164966 by Zaynal last updated on 24/Jan/22

⌊ (\frac{5}{x} + \frac{4}{x} + \frac{3}{x} + \frac{2}{x} + \frac{1}{x}) ∙ {(\frac{x}{1} - \frac{x}{2} - \frac{x}{3} - \frac{x}{4} - \frac{x}{5})}^{2} > \frac{1}{15} ⌋

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Answered by alephzero last updated on 24/Jan/22

\frac{15}{x} \times \frac{17^{2} x^{2}}{60^{2}} > \frac{1}{15}

\frac{289 x}{240} > \frac{1}{15}

\Rightarrow x > \frac{16}{289}