Menu Close

5cos-5-tsin-t-




Question Number 21591 by Isse last updated on 29/Sep/17
5cos^5 tsin t
5cos5tsint
Commented by mrW1 last updated on 29/Sep/17
what′s your concrete question?
whatsyourconcretequestion?
Answered by $@ty@m last updated on 29/Sep/17
Letcost=u   ⇒−sintdt=du   ∫5cos^5 tsin tdt  =∫5u^5 (−du)  =−5∫u^5 du  =−5(u^6 /6)+C  =((−5)/6)cos^6 t +C
Letcost=usintdt=du5cos5tsintdt=5u5(du)=5u5du=5u66+C=56cos6t+C

Leave a Reply

Your email address will not be published. Required fields are marked *