Question Number 190022 by Shrinava last updated on 26/Mar/23
$$\mathrm{5x}^{\mathrm{2}} \:−\:\mathrm{3x}\:+\:\mathrm{5}\:=\:\mathrm{0} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{x}\:+\:\frac{\mathrm{1}}{\mathrm{x}}\:=\:\mathrm{0} \\ $$
Commented by Rasheed.Sindhi last updated on 26/Mar/23
$$\mathrm{x}\:+\:\frac{\mathrm{1}}{\mathrm{x}}\:=\:\mathrm{0}\:,{What}\:{to}\:{find}? \\ $$
Commented by Shrinava last updated on 26/Mar/23
$$\mathrm{sorry}\:\mathrm{professor},\:\:\:\mathrm{x}\:+\:\frac{\mathrm{1}}{\mathrm{x}}\:=\:? \\ $$
Answered by SEKRET last updated on 26/Mar/23
$$\:\:\:\mathrm{5}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{5}=\:\mathrm{3}\boldsymbol{\mathrm{x}} \\ $$$$\:\:\:\mathrm{5}\boldsymbol{\mathrm{x}}\:+\:\frac{\mathrm{5}}{\boldsymbol{\mathrm{x}}}\:=\:\mathrm{3} \\ $$$$\:\:\boldsymbol{\mathrm{x}}\:+\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}\:=\:\frac{\mathrm{3}}{\mathrm{5}} \\ $$