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6-1-c-x-1-1-c-x-y-Express-11-1-c-x-1-1-c-x-in-terms-of-y-




Question Number 176785 by Ar Brandon last updated on 26/Sep/22
(6/(1+c^x ))+(1/(1+c^(−x) ))=y  Express  ((11)/(1+c^x ))+(1/(1+c^(−x) )) in terms of y
61+cx+11+cx=yExpress111+cx+11+cxintermsofy
Commented by Ar Brandon last updated on 26/Sep/22
Ans. 2y−1
Ans.2y1
Answered by a.lgnaoui last updated on 26/Sep/22
y=6(1/(1+c^x ))+(1/(1+(1/c^x )))=6(1/(1+c^x ))+(c^x /(1+c^x ))  y=6(1/(1+c^x ))+((1+c^x −1)/(1+c^x ))=5(1/(1+c^x ))+1  ((11)/(1+c^x ))+(1/(1+c^(−x) ))= ((11)/(1+c^x ))+1−(1/(1+c^x ))=10(1/(1+c^x ))+1  ((11)/(1+c^x ))+(1/(1+c^(−x) ))=2y−1
y=611+cx+11+1cx=611+cx+cx1+cxy=611+cx+1+cx11+cx=511+cx+1111+cx+11+cx=111+cx+111+cx=1011+cx+1111+cx+11+cx=2y1
Commented by Ar Brandon last updated on 26/Sep/22
Thank you, Sir!
Answered by mr W last updated on 26/Sep/22
((6+c^x )/(1+c^x ))=y  (5/(1+c^x ))=y−1    ((11)/(1+c^x ))+(1/(1+c^(−x) ))  =(6/(1+c^x ))+(1/(1+c^(−x) ))+(5/(1+c^x ))  =y+y−1  =2y−1
6+cx1+cx=y51+cx=y1111+cx+11+cx=61+cx+11+cx+51+cx=y+y1=2y1
Commented by Tawa11 last updated on 26/Sep/22
Great sirs
Greatsirs
Commented by Ar Brandon last updated on 26/Sep/22
Thank you, Sir!

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