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7-5-7-3-




Question Number 62051 by hhghg last updated on 14/Jun/19
(7^5 /7^3 )
$$\frac{\mathrm{7}^{\mathrm{5}} }{\mathrm{7}^{\mathrm{3}} } \\ $$
Commented by maxmathsup by imad last updated on 15/Jun/19
=7^(5−3)  =7^2  =49
$$=\mathrm{7}^{\mathrm{5}−\mathrm{3}} \:=\mathrm{7}^{\mathrm{2}} \:=\mathrm{49} \\ $$

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