Question Number 178166 by Spillover last updated on 13/Oct/22
![8.5g of hydrated copper (ii) sulphate CuSO_4 .xH_2 O was heated to dryness.if 4.0g of anhydrous copper (ii) sulphate[CuSO_4 ] obtain Find number of molecule of water of crystallization](https://www.tinkutara.com/question/Q178166.png)
$$\mathrm{8}.\mathrm{5g}\:\mathrm{of}\:\mathrm{hydrated}\:\mathrm{copper}\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{sulphate}\:\mathrm{CuSO}_{\mathrm{4}} .\mathrm{xH}_{\mathrm{2}} \mathrm{O}\:\mathrm{was}\:\mathrm{heated} \\ $$$$\mathrm{to}\:\mathrm{dryness}.\mathrm{if}\:\:\mathrm{4}.\mathrm{0g}\:\mathrm{of}\:\mathrm{anhydrous} \\ $$$$\mathrm{copper}\:\left(\mathrm{ii}\right)\:\mathrm{sulphate}\left[\mathrm{CuSO}_{\mathrm{4}} \right]\:\mathrm{obtain} \\ $$$$\mathrm{Find}\:\mathrm{number}\:\mathrm{of}\:\mathrm{molecule}\:\mathrm{of}\:\mathrm{water}\:\mathrm{of} \\ $$$$\mathrm{crystallization} \\ $$
Answered by MikeH last updated on 14/Oct/22
$$\:\:\mathrm{mass}\:\mathrm{of}\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\:=\:\mathrm{4}.\mathrm{5}\:\mathrm{g} \\ $$$$\mathrm{Empirical}\:\mathrm{Formula} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{CuSO}_{\mathrm{4}} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$$$\mathrm{moles}:\:\:\:\:\frac{\mathrm{4}.\mathrm{0}}{\mathrm{64}+\mathrm{32}+\mathrm{4}\left(\mathrm{16}\right)}\:\:\:\:\:\:\:\:\frac{\mathrm{4}.\mathrm{5}}{\mathrm{18}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{0}.\mathrm{025}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}.\mathrm{25} \\ $$$$\mathrm{mole}\:\mathrm{ratio}:\:\:\:\:\frac{\mathrm{0}.\mathrm{025}}{\mathrm{0}.\mathrm{025}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{0}.\mathrm{25}}{\mathrm{0}.\mathrm{025}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{10} \\ $$$$\Rightarrow\:\mathrm{CuSO}_{\mathrm{4}} .\mathrm{10}\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$
Commented by Spillover last updated on 16/Oct/22
$${thanks} \\ $$