Menu Close

8x-3-2x-dx-




Question Number 164681 by Zaynal last updated on 20/Jan/22
∫ (−8x(√(3−2x)) )dx
$$\int\:\left(−\mathrm{8}\boldsymbol{{x}}\sqrt{\mathrm{3}−\mathrm{2}\boldsymbol{{x}}}\:\right)\boldsymbol{{dx}} \\ $$
Answered by Ar Brandon last updated on 20/Jan/22
=4∫(3−2x−3)(√(3−2x))dx  =4∫((3−2x)^(3/2) −3(3−2x)^(1/2) )dx
$$=\mathrm{4}\int\left(\mathrm{3}−\mathrm{2}{x}−\mathrm{3}\right)\sqrt{\mathrm{3}−\mathrm{2}{x}}{dx} \\ $$$$=\mathrm{4}\int\left(\left(\mathrm{3}−\mathrm{2}{x}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{3}\left(\mathrm{3}−\mathrm{2}{x}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right){dx} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *