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a-1-0-a-2-1-a-n-2-a-n-1-a-n-a-885-




Question Number 186688 by norboyev last updated on 08/Feb/23
a_1 =0  a_2 =1  a_(n+2) =a_(n+1) −a_n   a_(885) =?
$${a}_{\mathrm{1}} =\mathrm{0} \\ $$$${a}_{\mathrm{2}} =\mathrm{1} \\ $$$${a}_{{n}+\mathrm{2}} ={a}_{{n}+\mathrm{1}} −{a}_{{n}} \\ $$$${a}_{\mathrm{885}} =? \\ $$
Commented by mr W last updated on 08/Feb/23
 determinant ((n,0,1,2,3,4,5,6,7,8,9),(a_n ,0,1,1,0,(−1),(−1),0,1,1,0))  a_(3n) =0  a_(3n+1) =(−1)^n   a_(3n+2) =(−1)^n   ⇒a_(885) =a_(3×295) =0
$$\begin{array}{|c|c|}{{n}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{2}}&\hline{\mathrm{3}}&\hline{\mathrm{4}}&\hline{\mathrm{5}}&\hline{\mathrm{6}}&\hline{\mathrm{7}}&\hline{\mathrm{8}}&\hline{\mathrm{9}}\\{{a}_{{n}} }&\hline{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}&\hline{−\mathrm{1}}&\hline{−\mathrm{1}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}\\\hline\end{array} \\ $$$${a}_{\mathrm{3}{n}} =\mathrm{0} \\ $$$${a}_{\mathrm{3}{n}+\mathrm{1}} =\left(−\mathrm{1}\right)^{{n}} \\ $$$${a}_{\mathrm{3}{n}+\mathrm{2}} =\left(−\mathrm{1}\right)^{{n}} \\ $$$$\Rightarrow{a}_{\mathrm{885}} ={a}_{\mathrm{3}×\mathrm{295}} =\mathrm{0} \\ $$

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