a-1-b-b-2-b-1-c-c-2-c-ab-a-2-b-2-solve-for-a-b-c-

Question Number 55888 by behi83417@gmail.com last updated on 05/Mar/19

a = 1 + b + b^{2}

b = 1 + c + c^{2}

c = ab + a^{2} + b^{2}

solve for : a, b, c .

Answered by MJS last updated on 06/Mar/19

no real solution

(\begin{matrix} a \\ b \\ c \end{matrix}) \in {(\begin{matrix} - . 209 \pm . 203 i \\ - . 397 \pm . 985 i \\ - . 927 \mp 1 . 15 i \end{matrix}), (\begin{matrix} . 442 \pm 1 . 73 i \\ - 1.35 \mp 1 . 02 i \\ - . 841 \pm 1 . 49 i \end{matrix}), (\begin{matrix} . 703 \pm . 458 i \\ - . 0453 \pm . 504 i \\ - . 230 \pm . 932 i \end{matrix}), (\begin{matrix} - . 936 \mp 2 . 09 i \\ - 1.21 \pm 1 . 48 i \\ - . 00212 \pm 1 . 48 i \end{matrix})}

if needed I^{'} ll post more digits

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