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A-2-2-kg-block-starts-from-rest-on-a-rough-inclined-plane-that-makes-an-angle-of-25-with-the-horizontal-The-coefficient-of-kinetic-friction-is-0-25-As-the-block-goes-2-m-down-the-plane-the-mechani




Question Number 24716 by Tinkutara last updated on 25/Nov/17
A 2.2 kg block starts from rest on a  rough inclined plane that makes an  angle of 25° with the horizontal. The  coefficient of kinetic friction is 0.25. As  the block goes 2 m down the plane, the  mechanical energy of the Earth-block  system changes by
A2.2kgblockstartsfromrestonaroughinclinedplanethatmakesanangleof25°withthehorizontal.Thecoefficientofkineticfrictionis0.25.Astheblockgoes2mdowntheplane,themechanicalenergyoftheEarthblocksystemchangesby
Answered by ajfour last updated on 25/Nov/17
△U=mg△y  △K=(1/2)mv^2   △E=△U+△K =W_(ext)            =−(μmgcos 25°)s           =−(1/4)×2.2×10×2×cos 25°           =(−11cos 25°)J .           ≈ −10J .
U=mgyK=12mv2E=U+K=Wext=(μmgcos25°)s=14×2.2×10×2×cos25°=(11cos25°)J.10J.
Commented by Tinkutara last updated on 25/Nov/17
Thank you Sir!
ThankyouSir!

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