Question Number 190573 by sami123 last updated on 06/Apr/23
$$\hat {{a}}\mathrm{2}+\mathrm{2}{ab}+\hat {{b}}\mathrm{2} \\ $$
Commented by a.lgnaoui last updated on 06/Apr/23
$$\mathrm{1}\bullet{pour}\:{editer}\:\:{exposant}\left({a}^{\mathrm{2}} \right) \\ $$$${dans}\:{clavier}\:{ecrire}\:\:{a}\:\:{puis}\:\:\:\: \\ $$$$\:\:\blacksquare^{\blacksquare} \:\:\:\:{puis}\:\:\left[{taper}\:\mathrm{2}\Rightarrow\right. \\ $$$${Resultat}:\:\:\:\:\:\boldsymbol{{a}}^{\mathrm{2}} \\ $$$$\mathrm{2}\bullet{pour}\:{editer}\:\:{indice}\left(\boldsymbol{{a}}_{\boldsymbol{{i}}} \right) \\ $$$$\:\:{taper}\:{a}\:\:{puis}\:{aller}\:{au}\: \\ $$$${symbole}\:\:\:\blacksquare_{\blacksquare} \:\:\:\:{taper}\:\:\boldsymbol{{i}} \\ $$$$\:\mathrm{3}\bullet\:{pour}\:\:{taper}\:{vecteur}\:\:\:\overset{\rightarrow} {{V}}\:\:\: \\ $$$${ecrire}\:{V}\:\:\:\:{puis}\:\:\overset{\blacksquare} {\blacksquare}\:\:{taper}\:\rightarrow \\ $$$${Resultat}\:\::\:\:\:\:\overset{\rightarrow} {\boldsymbol{\mathrm{V}}} \\ $$$$\:\:\:\:{meme}\:{chose}\:\:{pour}\:\frown\smile\ast…\:\: \\ $$$$−−−−−− \\ $$$${question}\:{pour}\:{aide} \\ $$$$\:{redimension}\:\:\:?\: \\ $$$${du}\:\:{texte}\:\:\left({taille}\:{courte}\right) \\ $$$$\:\:{exemple} \\ $$$$\:\:−−−−− \\ $$$$\:\:{Mr} \\ $$$$\:\:{Mr} \\ $$$${sometimes}\:{we}\:{need}\:{write} \\ $$$${answer}\:{for}\:{long}\:{equation} \\ $$$${but}\:{it}\:{tske}\:{long}\:{line}\:{to}\:{edit} \\ $$$${so}\:\:{can}\:\:{any}\:\:{one}\:{show}\:\:{me}\:{procede}\:\:{automatic} \\ $$$$\:{procedure}\:{to}\:{convert}\:\:{to}\:{smal}\:\:{texte}\:{for}\: \\ $$$${looking}\:{easy}\:\:{a}\:{total}\:{line}\:{of}\:{texte}? \\ $$$$ \\ $$
Commented by manolex last updated on 06/Apr/23
$${Ignaoui} \\ $$$${cursor}\:{next}\:{i} \\ $$$${select}\:\leftarrow\leftarrow\leftarrow\leftarrow\leftarrow\leftarrow\leftarrow\:\vdots\left({inf}.{right}\right)\:\:\:\:\:\:{A}\blacktriangle\:{A}\blacktriangle\:{A}\blacktriangle\: \\ $$$${Ignaoui} \\ $$
Commented by a.lgnaoui last updated on 06/Apr/23
$${thank}\:{you}\: \\ $$
Answered by Skabetix last updated on 07/Apr/23
$${a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} =\left({a}+{b}\right)^{\mathrm{2}} \\ $$