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a-2-b-2-c-2-2019-a-b-c-are-prime-numbers-how-many-possible-triples-of-a-b-c-which-that-suitable-for-equation-above-




Question Number 51950 by naka3546 last updated on 01/Jan/19
a^2  + b^2  + c^2   =  2019  a, b, c   are  prime  numbers .  how  many  possible  triples  of  (a, b, c)  which  that  suitable  for  equation  above .
a2+b2+c2=2019a,b,careprimenumbers.howmanypossibletriplesof(a,b,c)whichthatsuitableforequationabove.
Answered by afachri last updated on 01/Jan/19
Commented by naka3546 last updated on 01/Jan/19
how  to  get  it  ?
howtogetit?
Answered by mr W last updated on 02/Jan/19
say a≤b≤c  c≤(√(2019−2))≈45, i.e. the largest prime  could max. be 43.  ⇒a,b,c ∈(2,3,5,7,11,13,17,19,23,29,31,37,41,43)  the squares of these numbers are  n       n^2   1        1  2        4  3        9  5        25  7        49  11     121  13     169  17     289  19     361  23     529  29     841  31     961  37     1369  41     1681  43     1849    we start with c  c=43:  a^2 +b^2 =2019−1849=170  ⇒b=13, a=1  •    ⇒b=11, a=7  •    c=41:  a^2 +b^2 =2019−1681=338  b=17⇒a^2 =338−289=49⇒a=7  •  b=13⇒a^2 =338−13^2 =169⇒a=13  •  b=11⇒a^2 =338−11^2 =217⇒no sol. for a≤11  ⇒no further solution for b<11    c=37:  a^2 +b^2 =2019−1369=650  b=23⇒a^2 =650−529=121⇒a=11  •  b=19⇒a^2 =650−361=289⇒a=17  •  b=17⇒a^2 =650−289=361⇒no sol. for a≤17  ⇒no further solution for b<17    c=31:  a^2 +b^2 =2019−961=1058  b=31⇒a^2 =1058−961=97⇒no sol. for a≤31  b=29⇒a^2 =1058−841=217⇒no sol. for a≤29  b=23⇒a^2 =1058−529=529⇒a=23  •  ⇒no further solution for b<23    c=29:  a^2 +b^2 =2019−841=1178  b=29⇒a^2 =1178−841=337⇒no sol. for a≤29  b=23⇒a^2 =1178−529=649⇒no sol. for a≤23  ⇒no further solution for b<23    ⇒no further solution for c<29    ⇒all solutions are   (1, 13, 43)  (7, 11, 43)  (7, 17, 41)  (13, 13, 41)  (11, 23, 37)  (17, 19, 37)  (23, 23, 31)
sayabcc2019245,i.e.thelargestprimecouldmax.be43.a,b,c(2,3,5,7,11,13,17,19,23,29,31,37,41,43)thesquaresofthesenumbersarenn211243952574911121131691728919361235292984131961371369411681431849westartwithcc=43:a2+b2=20191849=170b=13,a=1b=11,a=7c=41:a2+b2=20191681=338b=17a2=338289=49a=7b=13a2=338132=169a=13b=11a2=338112=217nosol.fora11nofurthersolutionforb<11c=37:a2+b2=20191369=650b=23a2=650529=121a=11b=19a2=650361=289a=17b=17a2=650289=361nosol.fora17nofurthersolutionforb<17c=31:a2+b2=2019961=1058b=31a2=1058961=97nosol.fora31b=29a2=1058841=217nosol.fora29b=23a2=1058529=529a=23nofurthersolutionforb<23c=29:a2+b2=2019841=1178b=29a2=1178841=337nosol.fora29b=23a2=1178529=649nosol.fora23nofurthersolutionforb<23nofurthersolutionforc<29allsolutionsare(1,13,43)(7,11,43)(7,17,41)(13,13,41)(11,23,37)(17,19,37)(23,23,31)

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