a-2-b-2-c-2-2019-a-b-c-are-prime-numbers-how-many-possible-triples-of-a-b-c-which-that-suitable-for-equation-above- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 51950 by naka3546 last updated on 01/Jan/19 a2+b2+c2=2019a,b,careprimenumbers.howmanypossibletriplesof(a,b,c)whichthatsuitableforequationabove. Answered by afachri last updated on 01/Jan/19 Commented by naka3546 last updated on 01/Jan/19 howtogetit? Answered by mr W last updated on 02/Jan/19 saya⩽b⩽cc⩽2019−2≈45,i.e.thelargestprimecouldmax.be43.⇒a,b,c∈(2,3,5,7,11,13,17,19,23,29,31,37,41,43)thesquaresofthesenumbersarenn211243952574911121131691728919361235292984131961371369411681431849westartwithcc=43:a2+b2=2019−1849=170⇒b=13,a=1∙⇒b=11,a=7∙c=41:a2+b2=2019−1681=338b=17⇒a2=338−289=49⇒a=7∙b=13⇒a2=338−132=169⇒a=13∙b=11⇒a2=338−112=217⇒nosol.fora⩽11⇒nofurthersolutionforb<11c=37:a2+b2=2019−1369=650b=23⇒a2=650−529=121⇒a=11∙b=19⇒a2=650−361=289⇒a=17∙b=17⇒a2=650−289=361⇒nosol.fora⩽17⇒nofurthersolutionforb<17c=31:a2+b2=2019−961=1058b=31⇒a2=1058−961=97⇒nosol.fora⩽31b=29⇒a2=1058−841=217⇒nosol.fora⩽29b=23⇒a2=1058−529=529⇒a=23∙⇒nofurthersolutionforb<23c=29:a2+b2=2019−841=1178b=29⇒a2=1178−841=337⇒nosol.fora⩽29b=23⇒a2=1178−529=649⇒nosol.fora⩽23⇒nofurthersolutionforb<23⇒nofurthersolutionforc<29⇒allsolutionsare(1,13,43)(7,11,43)(7,17,41)(13,13,41)(11,23,37)(17,19,37)(23,23,31) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Q-f-x-a-x-b-x-g-x-f-x-f-x-2-g-3-Next Next post: Question-117486 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.