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Question Number 151174 by mathdanisur last updated on 18/Aug/21
((a+(√(3∙((a+(√(3∙((a+(√(3∙...))))^(1/3) ))))^(1/3) ))))^(1/3) = 3 find a=?
a+3⋅a+3⋅a+3⋅…333=3finda=?
Answered by mr W last updated on 18/Aug/21
((a+(√(3×3))))^(1/3) =3 a+3=27 a=24
a+3×33=3a+3=27a=24
Commented by mathdanisur last updated on 18/Aug/21
Thankyou Ser
ThankyouSer
Answered by maged last updated on 18/Aug/21
let ((a+(√(3∙((a+(√(3∙((a+(√(3∙...))))^(1/3) ))))^(1/3) ))))^(1/3) = u ⇒u=3 ((a+(√(3u))))^(1/3) =3 a+(√(3u))=27 a+(√9)=27 a=27−3 a=24
leta+3⋅a+3⋅a+3⋅…333=u⇒u=3a+3u3=3a+3u=27a+9=27a=27−3a=24
Commented by mathdanisur last updated on 18/Aug/21
Thankyou Ser
ThankyouSer

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