Question Number 52340 by Necxx last updated on 06/Jan/19
$${A}\:\mathrm{90}{cm}\:{uniform}\:{lever}\:{has}\:{a}\:{load} \\ $$$${of}\:\mathrm{30}{N}\:{suspended}\:{at}\:\mathrm{15}{cm}\:{from} \\ $$$${one}\:{of}\:{its}\:{ends}.{If}\:{the}\:{fulcrum}\:{is}\:{at} \\ $$$${the}\:{centre}\:{of}\:{gravity}\:{what}\:{is}\:{the} \\ $$$${force}\:{that}\:{must}\:{be}\:{applied}\:{to}\:{its} \\ $$$${other}\:{end}\:{to}\:{keep}\:{it}\:{in}\:{horizontal} \\ $$$${equilibrium}? \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 06/Jan/19
$${F}×\mathrm{45}=\mathrm{30}×\mathrm{30} \\ $$$${F}=\mathrm{20}{N}\:\:{moment}\:{taken}\:{about}\:{fulcrum} \\ $$