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a-b-4-and-cos-60-find-a-b-




Question Number 149045 by mathdanisur last updated on 02/Aug/21
∣a^(→) ∣ = ∣b^(→) ∣ = 4   and   cos𝛂 = 60°  find   a^(→)  ∙ b^(→)  = ?
$$\mid\overset{\rightarrow} {\boldsymbol{{a}}}\mid\:=\:\mid\overset{\rightarrow} {\boldsymbol{{b}}}\mid\:=\:\mathrm{4}\:\:\:{and}\:\:\:{cos}\boldsymbol{\alpha}\:=\:\mathrm{60}° \\ $$$${find}\:\:\:\overset{\rightarrow} {\boldsymbol{{a}}}\:\centerdot\:\overset{\rightarrow} {\boldsymbol{{b}}}\:=\:? \\ $$
Answered by puissant last updated on 02/Aug/21
a^→ .b^→ =∣a^→ ∣×∣b^→ ∣×cosα  α=mes(a^→ ;b^→ )  ⇒ a^→ .b^→ =4×4×cos60 = 8...
$$\overset{\rightarrow} {\mathrm{a}}.\overset{\rightarrow} {\mathrm{b}}=\mid\overset{\rightarrow} {\mathrm{a}}\mid×\mid\overset{\rightarrow} {\mathrm{b}}\mid×\mathrm{cos}\alpha \\ $$$$\alpha=\mathrm{mes}\left(\overset{\rightarrow} {\mathrm{a}};\overset{\rightarrow} {\mathrm{b}}\right) \\ $$$$\Rightarrow\:\overset{\rightarrow} {\mathrm{a}}.\overset{\rightarrow} {\mathrm{b}}=\mathrm{4}×\mathrm{4}×\mathrm{cos60}\:=\:\mathrm{8}… \\ $$
Commented by mathdanisur last updated on 02/Aug/21
Thank You Ser
$${Thank}\:{You}\:{Ser} \\ $$

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