a-b-b-a-1-a-b-a-b-0-

Question Number 83477 by M±th+et£s last updated on 02/Mar/20

a^{b} + b^{a} = 1 a = ?, b = ?

a \neq b \neq 0

Commented by mr W last updated on 03/Mar/20

i f a, b \in R, t h e n i t h i n k t h e r e i s n o

s o l u t i o n f o r a \neq b \neq 0 .

Facebook Tweet Pin