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a-b-c-0-Find-the-value-of-b-c-a-c-a-b-a-b-c-a-b-c-b-c-a-c-a-b-

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Question Number 161356 by naka3546 last updated on 17/Dec/21
a + b + c = 0 Find the value of (((b−c)/a) + ((c−a)/b) + ((a−b)/c))((a/(b−c)) + (b/(c−a)) + (c/(a−b))) .
a+b+c=0Findthevalueof(b−ca+c−ab+a−bc)(ab−c+bc−a+ca−b).
Commented by MJS_new last updated on 17/Dec/21
9
9
Commented by naka3546 last updated on 17/Dec/21
Show your workings, please, sir.
Showyourworkings,please,sir.
Answered by MJS_new last updated on 17/Dec/21
c=−(a+b) ⇒ ((b−c)/a)+((c−a)/b)++((a−b)/c)=−(((a−b)(a+2b)(2a+b))/(a(a+b)b)) (a/(b−c))+(b/(c−a))+(c/(a−b))=−((9a(a+b)b)/((a−b)(a+2b)(2a+b))) ⇒ answer is 9
c=−(a+b)⇒b−ca+c−ab++a−bc=−(a−b)(a+2b)(2a+b)a(a+b)bab−c+bc−a+ca−b=−9a(a+b)b(a−b)(a+2b)(2a+b)⇒answeris9
Commented by naka3546 last updated on 17/Dec/21
Thank you, sir.
Thankyou,sir.

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