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a-b-c-5-a-5-b-5-c-5-a-b-c-3-a-3-b-3-c-3-is-there-an-easier-way-




Question Number 184505 by SEKRET last updated on 07/Jan/23
   (((a+b+c)^5 −a^5 −b^5 −c^5 )/((a+b+c)^3 −a^3 −b^3 −c^3 )) = ?   is there an  easier  way.
(a+b+c)5a5b5c5(a+b+c)3a3b3c3=?isthereaneasierway.
Answered by Frix last updated on 07/Jan/23
=((5(a+b)(a+c)(b+c)(a^2 +b^2 +c^2 +ab+ac+bc))/(3(a+b)(a+c)(b+c)))  I found no easier way
=5(a+b)(a+c)(b+c)(a2+b2+c2+ab+ac+bc)3(a+b)(a+c)(b+c)Ifoundnoeasierway
Commented by SEKRET last updated on 08/Jan/23
  thanks  sir
thankssir

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