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a-b-c-a-a-b-b-c-c-abc-a-b-c-3-




Question Number 121170 by pooooop last updated on 05/Nov/20
      (a;b;c)∈∀   a^a ∙ b^b ∙ c^c ≥(abc)^((a+b+c)/3)
$$\:\:\:\:\:\:\left(\boldsymbol{{a}};\boldsymbol{{b}};\boldsymbol{{c}}\right)\in\forall \\ $$$$\:\boldsymbol{{a}}^{\boldsymbol{{a}}} \centerdot\:\boldsymbol{{b}}^{\boldsymbol{{b}}} \centerdot\:\boldsymbol{{c}}^{\boldsymbol{{c}}} \geqslant\left(\boldsymbol{{abc}}\right)^{\frac{\boldsymbol{{a}}+\boldsymbol{{b}}+\boldsymbol{{c}}}{\mathrm{3}}} \\ $$

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