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Question Number 126104 by Mathgreat last updated on 17/Dec/20
((a+b)/c) + ((b+c)/a) +((a+c)/b) ≥ 4a−3b+c a≥b≥c
$$\frac{{a}+{b}}{{c}}\:+\:\frac{{b}+{c}}{{a}}\:+\frac{{a}+{c}}{{b}}\:\geqslant\:\mathrm{4}{a}−\mathrm{3}{b}+{c} \\ $$$${a}\geqslant{b}\geqslant{c} \\ $$
Commented by Mathgreat last updated on 17/Dec/20
prove
$$\boldsymbol{{prove}} \\ $$

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