a-b-c-gt-0-a-2-b-2-c-2-2-prove-a-6-b-6-c-6-3-a-5-b-5-c-5-4-

Question Number 145772 by mathdanisur last updated on 07/Jul/21

a; b; c > 0; a^{2} + b^{2} + c^{2} = 2 p r o v e :

{(a^{6} + b^{6} + c^{6})}^{3} ⩾ {(a^{5} + b^{5} + c^{5})}^{4}