a-b-c-N-5a-6b-9c-abc-min- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 188156 by Shrinava last updated on 26/Feb/23 a,b,c∈N5a=6b=9c(abc)\boldsymbolmin=? Answered by mr W last updated on 26/Feb/23 5a=6b=9c=n5a=2×3b=32c=n⇒nmin=5×2×32=90[ornmin=lcm(5,6,9)=90]⇒amin=905=18⇒bmin=906=15⇒cmin=909=10⇒(abc)min=18×15×10=2700✓ Commented by Shrinava last updated on 26/Feb/23 cooldearprofessorthankyoucooldearprofessorthankyou Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Find-the-limits-at-0-0-of-the-following-functions-1-f-x-y-x-2-y-2-x-2-y-2-2-f-x-y-xy-x-2-y-2-3-f-x-y-xy-x-y-4-f-x-y-x-2-y-2-x-2-y-2-5-fNext Next post: Prove-the-equality-n-k-0-n-1-k-n-k-n-k-n- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![5a = 6b = 9c=n 5a = 2×3b = 3^2 c=n ⇒n_(min) =5×2×3^2 =90 [or n_(min) =lcm(5,6,9)=90] ⇒a_(min) =((90)/5)=18 ⇒b_(min) =((90)/6)=15 ⇒c_(min) =((90)/9)=10 ⇒(abc)_(min) =18×15×10=2700 ✓](https://www.tinkutara.com/question/Q188160.png)
