Menu Close

a-b-c-R-b-c-d-a-a-c-d-b-a-b-c-d-a-b-d-c-r-what-is-r-

Tinku Tara 0 Comments
Pin




Question Number 80108 by jagoll last updated on 31/Jan/20
a,b,c ∈R ((b+c+d)/a)=((a+c+d)/b)=((a+b+c)/d)=((a+b+d)/c)=r what is r?
a,b,c∈Rb+c+da=a+c+db=a+b+cd=a+b+dc=rwhatisr?
Commented by john santu last updated on 31/Jan/20
a+b+c+d = x ((x−a)/a)=((x−b)/b)=((x−d)/d)=((x−c)/c)=r (1)bx−ab=ax−ab ⇒(a−b)x=0 a=b ∨x =0 (2) dx−bd=bx−bd ⇒b=d (3) cx−cd=dx−cd ⇒c=d ∴ a=b=c=d ⇒r = ((b+c+d)/a)=((3a)/a) = 3 for x = 0 ⇒b+c+d = −a r = ((b+c+d)/a)=−1
a+b+c+d=xx−aa=x−bb=x−dd=x−cc=r(1)bx−ab=ax−ab⇒(a−b)x=0a=b∨x=0(2)dx−bd=bx−bd⇒b=d(3)cx−cd=dx−cd⇒c=d∴a=b=c=d⇒r=b+c+da=3aa=3forx=0⇒b+c+d=−ar=b+c+da=−1
Commented by jagoll last updated on 31/Jan/20
thanks
thanks
Commented by $@ty@m123 last updated on 31/Jan/20
When x=0, r=((x−a)/a)=−1
Whenx=0,r=x−aa=−1
Answered by mr W last updated on 31/Jan/20
b+c+d=ra a+c+d=rb a+b+d=rc a+b+c=rd Σ: 3(a+b+c+d)=r(a+b+c+d) if a+b+c+d≠0 ⇒r=3 if a+b+c+d=0: ⇒r=−1
b+c+d=raa+c+d=rba+b+d=rca+b+c=rdΣ:3(a+b+c+d)=r(a+b+c+d)ifa+b+c+d≠0⇒r=3ifa+b+c+d=0:⇒r=−1
Commented by john santu last updated on 31/Jan/20
wrong sir. a+b+c+d=0 b+c+d = −a (clear ! ) r = ((b+c+d)/a) =−1
wrongsir.a+b+c+d=0b+c+d=−a(clear!)r=b+c+da=−1
Commented by mr W last updated on 31/Jan/20
if a+b+c+d=0 ⇒r=−1 this is correct.
ifa+b+c+d=0⇒r=−1thisiscorrect.

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *