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A-bag-contains-6-white-4-red-amp-10-black-balls-If-two-balls-are-drawn-at-random-what-is-the-probability-of-both-being-black-




Question Number 106405 by john santu last updated on 05/Aug/20
A bag contains 6 white, 4 red & 10  black balls. If two balls are drawn  at random, what is the  probability of both being black ?
$$\mathrm{A}\:\mathrm{bag}\:\mathrm{contains}\:\mathrm{6}\:\mathrm{white},\:\mathrm{4}\:\mathrm{red}\:\&\:\mathrm{10} \\ $$$$\mathrm{black}\:\mathrm{balls}.\:\mathrm{If}\:\mathrm{two}\:\mathrm{balls}\:\mathrm{are}\:\mathrm{drawn} \\ $$$$\mathrm{at}\:\mathrm{random},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{probability}\:\mathrm{of}\:\mathrm{both}\:\mathrm{being}\:\mathrm{black}\:? \\ $$
Answered by bemath last updated on 05/Aug/20
p(A) = ((C _2^(10) )/(C _2^(20) )) = ((45)/(190)) = (9/(38))
$$\mathrm{p}\left(\mathrm{A}\right)\:=\:\frac{\mathrm{C}\:_{\mathrm{2}} ^{\mathrm{10}} }{\mathrm{C}\:_{\mathrm{2}} ^{\mathrm{20}} }\:=\:\frac{\mathrm{45}}{\mathrm{190}}\:=\:\frac{\mathrm{9}}{\mathrm{38}}\: \\ $$

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