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A-ball-is-thrown-up-in-a-lift-with-a-velocity-u-relative-to-the-lift-If-it-returns-to-the-lift-in-time-t-then-acceleration-of-the-lift-is-Answer-2u-gt-t-upwards-




Question Number 16623 by Tinkutara last updated on 24/Jun/17
A ball is thrown up in a lift with a  velocity u relative to the lift. If it  returns to the lift in time t, then  acceleration of the lift is [Answer:  ((2u − gt)/t) upwards]
$$\mathrm{A}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{thrown}\:\mathrm{up}\:\mathrm{in}\:\mathrm{a}\:\mathrm{lift}\:\mathrm{with}\:\mathrm{a} \\ $$$$\mathrm{velocity}\:{u}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{lift}.\:\mathrm{If}\:\mathrm{it} \\ $$$$\mathrm{returns}\:\mathrm{to}\:\mathrm{the}\:\mathrm{lift}\:\mathrm{in}\:\mathrm{time}\:{t},\:\mathrm{then} \\ $$$$\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{lift}\:\mathrm{is}\:\left[\boldsymbol{\mathrm{Answer}}:\right. \\ $$$$\left.\frac{\mathrm{2}{u}\:−\:{gt}}{{t}}\:\mathrm{upwards}\right] \\ $$
Answered by ajfour last updated on 24/Jun/17
 s_(lift) =s_(ball)  in time t    (upward +ve)   (1/2)at^2  = ut−(1/2)gt^2    ⇒  a = (2/t^2 )(((2u−gt)/2))t = ((2u−gt)/t)  (↑) .
$$\:\mathrm{s}_{\mathrm{lift}} =\mathrm{s}_{\mathrm{ball}} \:\mathrm{in}\:\mathrm{time}\:\mathrm{t}\:\:\:\:\left(\mathrm{upward}\:+\mathrm{ve}\right) \\ $$$$\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{at}^{\mathrm{2}} \:=\:\mathrm{ut}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}^{\mathrm{2}} \\ $$$$\:\Rightarrow\:\:\mathrm{a}\:=\:\frac{\mathrm{2}}{\mathrm{t}^{\mathrm{2}} }\left(\frac{\mathrm{2u}−\mathrm{gt}}{\mathrm{2}}\right)\mathrm{t}\:=\:\frac{\mathrm{2u}−\mathrm{gt}}{\mathrm{t}}\:\:\left(\uparrow\right)\:. \\ $$
Commented by Tinkutara last updated on 24/Jun/17
Thanks Sir!
$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$

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