Question Number 190266 by alcohol last updated on 30/Mar/23
$${a}\:{ball}\:{is}\:{thrown}\:{vertically}\:{upward} \\ $$$${from}\:{a}\:{point}\:\mathrm{0}.\mathrm{5}{m}\:{above}\:{the}\:{ground}\:{with} \\ $$$${speed}\:{u}\:=\:\mathrm{7}{m}/{s} \\ $$$${find}\:{the}\:{height}\:{reached}\:{above}\:{ground} \\ $$$${g}\:=\:\mathrm{10}{m}/{s}^{\mathrm{2}} \\ $$
Answered by ARUNG_Brandon_MBU last updated on 30/Mar/23
$$\mathrm{v}^{\mathrm{2}} ={u}^{\mathrm{2}} −\mathrm{2}{gh}\: \\ $$$$\mathrm{0}=\mathrm{7}^{\mathrm{2}} −\mathrm{2}\left(\mathrm{10}\right){h}\:\Rightarrow{h}=\frac{\mathrm{49}}{\mathrm{20}}\:{m} \\ $$$$\mathrm{height}={h}+\mathrm{0}.\mathrm{5}=\mathrm{2}.\mathrm{95}\:{m} \\ $$