Question Number 22492 by Tinkutara last updated on 19/Oct/17
$$\mathrm{A}\:\mathrm{ball}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{400}\:\mathrm{g}\:\mathrm{travels}\:\mathrm{horizontally} \\ $$$$\mathrm{along}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{and}\:\mathrm{collides}\:\mathrm{with}\:\mathrm{a} \\ $$$$\mathrm{wall}.\:\mathrm{The}\:\mathrm{velocity}-\mathrm{time}\:\mathrm{graph}\:\mathrm{below} \\ $$$$\mathrm{represents}\:\mathrm{the}\:\mathrm{motion}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{for}\:\mathrm{the} \\ $$$$\mathrm{first}\:\mathrm{1}.\mathrm{2}\:\mathrm{seconds}. \\ $$$$\mathrm{The}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{average}\:\mathrm{force}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{ball}\:\mathrm{and}\:\mathrm{the}\:\mathrm{wall}\:\mathrm{is} \\ $$
Commented by Tinkutara last updated on 19/Oct/17
Answered by ajfour last updated on 19/Oct/17
$${F}_{{avg}} =\frac{{m}\bigtriangleup{v}}{\bigtriangleup{t}}\:=\frac{\left(\mathrm{0}.\mathrm{4}{kg}\right)\left(\mathrm{10}{m}/{s}\right)}{\left(\mathrm{0}.\mathrm{2}{s}\right)} \\ $$$$\:\:\:\:\:\:\:\:=\mathrm{20}{N}\:. \\ $$
Commented by Tinkutara last updated on 19/Oct/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$