Question Number 20984 by Tinkutara last updated on 09/Sep/17
$$\mathrm{A}\:\mathrm{ball}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{is}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{a} \\ $$$$\mathrm{velocity}\:{u}\:\mathrm{rebounds}\:\mathrm{from}\:\mathrm{a}\:\mathrm{wall}\:\mathrm{with} \\ $$$$\mathrm{same}\:\mathrm{speed}.\:\mathrm{The}\:\mathrm{collision}\:\mathrm{is}\:\mathrm{assumed} \\ $$$$\mathrm{to}\:\mathrm{be}\:\mathrm{elastic}\:\mathrm{and}\:\mathrm{the}\:\mathrm{force}\:\mathrm{of}\:\mathrm{interaction} \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{and}\:\mathrm{the}\:\mathrm{wall}\:\mathrm{varies}\:\mathrm{as} \\ $$$$\mathrm{shown}\:\mathrm{in}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{given}\:\mathrm{below}.\:\mathrm{The} \\ $$$$\mathrm{value}\:\mathrm{of}\:{F}_{{m}} \:\mathrm{is} \\ $$
Commented by Tinkutara last updated on 09/Sep/17
Answered by dioph last updated on 09/Sep/17
$$\Delta{P}\:=\:\mathrm{2}{mu} \\ $$$$\Delta{P}\:=\:\int_{\mathrm{0}} ^{\:\mathrm{2}{T}} {F}\left({t}\right){dt}\:=\:{F}_{{m}} {T} \\ $$$${F}_{{m}} {T}\:=\:\mathrm{2}{mu} \\ $$$${F}_{{m}} \:=\:\frac{\mathrm{2}{mu}}{{T}} \\ $$
Commented by Tinkutara last updated on 13/Sep/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$