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A-ball-of-p-of-mass-0-25kg-losses-1-3-of-its-velocity-when-it-makes-an-head-on-collision-with-an-identical-ball-q-at-rest-After-collision-q-moves-off-with-a-velocity-of-2ms-1-in-the-original




Question Number 175010 by Mastermind last updated on 16/Aug/22
 A ball of p of mass 0.25kg losses (1/3) of   its velocity when it makes an head on  collision with an identical ball q at rest.  After collision, q moves off with a velocity  of 2ms^(−1)  in the original direction of p.  Calculate the initial velocity of p.
$$\:\mathrm{A}\:\mathrm{ball}\:\mathrm{of}\:\boldsymbol{\mathrm{p}}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{25kg}\:\mathrm{losses}\:\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{of}\: \\ $$$$\mathrm{its}\:\mathrm{velocity}\:\mathrm{when}\:\mathrm{it}\:\mathrm{makes}\:\mathrm{an}\:\mathrm{head}\:\mathrm{on} \\ $$$$\mathrm{collision}\:\mathrm{with}\:\mathrm{an}\:\mathrm{identical}\:\mathrm{ball}\:\boldsymbol{\mathrm{q}}\:\mathrm{at}\:\mathrm{rest}. \\ $$$$\mathrm{After}\:\mathrm{collision},\:\boldsymbol{\mathrm{q}}\:\mathrm{moves}\:\mathrm{off}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity} \\ $$$$\mathrm{of}\:\mathrm{2ms}^{−\mathrm{1}} \:\mathrm{in}\:\mathrm{the}\:\mathrm{original}\:\mathrm{direction}\:\mathrm{of}\:\boldsymbol{\mathrm{p}}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{initial}\:\mathrm{velocity}\:\mathrm{of}\:\boldsymbol{\mathrm{p}}. \\ $$
Commented by mr W last updated on 16/Aug/22
pu=p((2u)/3)+qv  p=q  v=2 m/s  ⇒(u/3)=v  ⇒u=3v=6 m/s
$${pu}={p}\frac{\mathrm{2}{u}}{\mathrm{3}}+{qv} \\ $$$${p}={q} \\ $$$${v}=\mathrm{2}\:{m}/{s} \\ $$$$\Rightarrow\frac{{u}}{\mathrm{3}}={v} \\ $$$$\Rightarrow{u}=\mathrm{3}{v}=\mathrm{6}\:{m}/{s} \\ $$
Answered by MikeH last updated on 16/Aug/22
By PCLM  0.25 (u) = 0.25(u−(u/3)) + 0.25(2)  ⇒ 0.25u = 0.25(((2u)/3)) + 0.5  ⇒0.25 u = 3(0.5)  ⇒ u = 6 m/s  initial speed of P is 6 m/s
$$\mathrm{By}\:\mathrm{PCLM} \\ $$$$\mathrm{0}.\mathrm{25}\:\left({u}\right)\:=\:\mathrm{0}.\mathrm{25}\left({u}−\frac{{u}}{\mathrm{3}}\right)\:+\:\mathrm{0}.\mathrm{25}\left(\mathrm{2}\right) \\ $$$$\Rightarrow\:\mathrm{0}.\mathrm{25}{u}\:=\:\mathrm{0}.\mathrm{25}\left(\frac{\mathrm{2}{u}}{\mathrm{3}}\right)\:+\:\mathrm{0}.\mathrm{5} \\ $$$$\Rightarrow\mathrm{0}.\mathrm{25}\:{u}\:=\:\mathrm{3}\left(\mathrm{0}.\mathrm{5}\right) \\ $$$$\Rightarrow\:{u}\:=\:\mathrm{6}\:\mathrm{m}/\mathrm{s} \\ $$$$\mathrm{initial}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{P}\:\mathrm{is}\:\mathrm{6}\:\mathrm{m}/\mathrm{s}\: \\ $$
Commented by Tawa11 last updated on 16/Aug/22
Great sirs
$$\mathrm{Great}\:\mathrm{sirs} \\ $$

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