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A-ball-of-p-of-mass-0-25kg-losses-1-3-of-its-velocity-when-it-makes-an-head-on-collision-with-an-identical-ball-q-at-rest-After-collision-q-moves-off-with-a-velocity-of-2ms-1-in-the-original




Question Number 175010 by Mastermind last updated on 16/Aug/22
 A ball of p of mass 0.25kg losses (1/3) of   its velocity when it makes an head on  collision with an identical ball q at rest.  After collision, q moves off with a velocity  of 2ms^(−1)  in the original direction of p.  Calculate the initial velocity of p.
Aballofpofmass0.25kglosses13ofitsvelocitywhenitmakesanheadoncollisionwithanidenticalballqatrest.Aftercollision,qmovesoffwithavelocityof2ms1intheoriginaldirectionofp.Calculatetheinitialvelocityofp.
Commented by mr W last updated on 16/Aug/22
pu=p((2u)/3)+qv  p=q  v=2 m/s  ⇒(u/3)=v  ⇒u=3v=6 m/s
pu=p2u3+qvp=qv=2m/su3=vu=3v=6m/s
Answered by MikeH last updated on 16/Aug/22
By PCLM  0.25 (u) = 0.25(u−(u/3)) + 0.25(2)  ⇒ 0.25u = 0.25(((2u)/3)) + 0.5  ⇒0.25 u = 3(0.5)  ⇒ u = 6 m/s  initial speed of P is 6 m/s
ByPCLM0.25(u)=0.25(uu3)+0.25(2)0.25u=0.25(2u3)+0.50.25u=3(0.5)u=6m/sinitialspeedofPis6m/s
Commented by Tawa11 last updated on 16/Aug/22
Great sirs
Greatsirs

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