A-ball-rolled-on-ice-with-a-velocity-of-14-ms-1-comes-to-rest-after-travelling-40-m-Find-the-coefficient-of-friction-Given-g-9-8-m-s-2-

Question Number 20349 by Tinkutara last updated on 25/Aug/17

A ball rolled on ice with a velocity of

14 {ms}^{- 1} comes to rest after travelling

40 m . Find the coefficient of friction .

(Given, g = 9.8 m / s^{2})

Commented by Tinkutara last updated on 25/Aug/17

Just tell the answer . Is it 0.25 or 0.5 ?

Commented by ajfour last updated on 25/Aug/17

f a u l t y q u e s t i o n, n o t c l e a r w h e t h e r

b a l l r o l l s o r j u s t s l i d e s, w h a t t y p e

o f b a l l, w h a t r a d i u s \dots

d i d i t s t a r t r o l l i n g s i n c e b e g i n n i n g

i t s h o u l d n o t s t o p, f r i c t i o n w o n t

e v e n a c t t h e n

i f i t j u s t s l i d e s t h e n

μ m g x = \frac{1}{2} {m v}^{2}

\Rightarrow μ = \frac{v^{2}}{2 g x} = \frac{196}{2 \times 9.8 \times 40} = 0.25

Commented by Tinkutara last updated on 25/Aug/17

Thanks, 0.25 I wanted .