A-bicycle-has-a-constant-velocity-of-10-m-s-A-person-starts-from-rest-and-runs-to-catch-up-to-the-bicycle-in-30-s-What-is-the-acceleration-of-the-person-

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Question Number 171332 by Tawa11 last updated on 12/Jun/22

A bicycle has a constant velocity of 10 m/s. A person starts from rest and runs to catch up to the bicycle in 30 s. What is the acceleration of the person?

Commented by Tawa11 last updated on 12/Jun/22

I work towards answer to get 300 = 450a, a = (2/3) m/s^2 . I want to know why the bicycle time too is 30sec. Since the question did not indicate equal time. For bicycle: s = vt = 10(30) = 300m For person: s = (1/2)at^2 = (1/2) × a × 30^2 = (1/2) × a × 900 = 450a Equal distance 300 = 450a

I work towards answer to get

300 = 450 a, a = \frac{2}{3} m / s^{2} .

I want to know why the bicycle time too is 30 \sec .

Since the question did not indicate equal time .

For bicycle : s = vt = 10 (30) = 300 m

For person : s = \frac{1}{2} {at}^{2} = \frac{1}{2} \times a \times 30^{2} = \frac{1}{2} \times a \times 900 = 450 a

Equal distance

300 = 450 a

Commented by Tawa11 last updated on 12/Jun/22

Or the question means that they both start from the beginning. And the person still be in the same position as the bicycle after 30 seconds?

Or the question means that they both start from the beginning .

And the person still be in the same position as the bicycle after 30 seconds ?

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