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A-block-of-mass-m-is-connected-with-another-block-of-mass-2m-by-a-light-spring-2m-is-connected-with-a-hanging-mass-3m-by-an-inextensible-light-string-At-the-time-of-release-of-block-3m-find-tension




Question Number 21388 by Tinkutara last updated on 22/Sep/17
A block of mass m is connected with  another block of mass 2m by a light  spring. 2m is connected with a hanging  mass 3m by an inextensible light string.  At the time of release of block 3m, find  tension in the string and acceleration  of all the masses.
Ablockofmassmisconnectedwithanotherblockofmass2mbyalightspring.2misconnectedwithahangingmass3mbyaninextensiblelightstring.Atthetimeofreleaseofblock3m,findtensioninthestringandaccelerationofallthemasses.
Commented by Tinkutara last updated on 22/Sep/17
Commented by mrW1 last updated on 22/Sep/17
since the string is inextensible,   “2m” and “3m” have the same  velocity and acceleration.    let T=tension in the string  let a=acceleration of “2m” and “3m”    3mg−T=3ma  T=2ma  ⇒a=(3/5)g=0.6g  ⇒T=(6/5)mg=1.2mg    the elongation of the spring is zero,  therefore the force in it is also zero.  ⇒the acceleration of “m” is zero.
sincethestringisinextensible,2mand3mhavethesamevelocityandacceleration.letT=tensioninthestringleta=accelerationof2mand3m3mgT=3maT=2maa=35g=0.6gT=65mg=1.2mgtheelongationofthespringiszero,thereforetheforceinitisalsozero.theaccelerationofmiszero.
Commented by Tinkutara last updated on 23/Sep/17
Thank you very much Sir!
ThankyouverymuchSir!
Commented by mrW1 last updated on 23/Sep/17
at t=0 the displacement of “2m”is  zero, therefore the force in the spring  between “m” and “2m” is zero.   ⇒acceleration of “m” is zero at t=0.  this is independent from which mass  it has.
att=0thedisplacementof2miszero,thereforetheforceinthespringbetweenmand2miszero.accelerationofmiszeroatt=0.thisisindependentfromwhichmassithas.

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