Question Number 32585 by rahul 19 last updated on 28/Mar/18
![A body undergoing SHM about the origin has its equation x=0.2cos 5πt. Find its average speed from t=0 to t=0.7 sec.](https://www.tinkutara.com/question/Q32585.png)
Commented by rahul 19 last updated on 28/Mar/18
![](https://www.tinkutara.com/question/3867.png)
Commented by rahul 19 last updated on 28/Mar/18
![pls explain this: t=((nT)/4)+t_0 ..........](https://www.tinkutara.com/question/Q32604.png)
Answered by Joel578 last updated on 28/Mar/18
![x(t) = 0.2 cos (5πt) x(0) = 0.2 cos (0) = 0.2 x(0.7) = 0.2 cos ((7/2)π) = 0 v^− = ((Δx)/(Δt)) = ((0.2)/(0.7)) = (2/7) ms^(−1)](https://www.tinkutara.com/question/Q32596.png)
Commented by rahul 19 last updated on 28/Mar/18
![ans. given is 2 m/s.](https://www.tinkutara.com/question/Q32598.png)
Answered by tanmay.chaudhury50@gmail.com last updated on 20/May/18
![average speed=((x_2 −x_1 )/(t_2 −t_1 )) =((0.2cos(5Π×0.7)−0.2cos(5Π×0))/(0.7−0.0)) ={0.2cos(((5×22×0.7)/7))−0.2}/0.7 =((0.2(cos11)−0.2)/(0.7)) =(2/7)×{(cos11)−1} =(2/7)×(0.0044256−1) =−0.2844 pls check](https://www.tinkutara.com/question/Q35597.png)
Commented by tanmay.chaudhury50@gmail.com last updated on 20/May/18
![](https://www.tinkutara.com/question/4156.png)
Answered by ajfour last updated on 20/May/18
![Time period=((2π)/(5π))=0.4s Distance traveled in 0.7s (=((7T)/4)) is = 7A =7×0.2 =1.4 units Average speed for this duration = ((1.4units)/(0.7s)) = 2units/s .](https://www.tinkutara.com/question/Q35604.png)