Question Number 42698 by Rio Michael last updated on 31/Aug/18
$${A}\:{boy}\:{lying}\:{flat}\:{on}\:{level}\:{ground}\:{sees}\:{a}\:{bird}\:\:{on}\:{a}\:{tree}\:{and}\:{the} \\ $$$${angle}\:{of}\:{Elevation}\:{from}\:{the}\:{boy}\:{to}\:{the}\:{birth}\:{is}\:\mathrm{42}°,{if}\:{the}\:{boy} \\ $$$${is}\:\mathrm{6}{m}\:{from}\:{the}\:{tree}.{find}\:{the}\:{hieght}\:{of}\:{the}\:{tree}\:{if}\:{the}\:{bird} \\ $$$${is}\:{at}\:{the}\:{top}\:{of}\:{the}\:{tree} \\ $$
Answered by math1967 last updated on 31/Aug/18
$$\frac{{Height}\:{of}\:{tree}}{\mathrm{6}}={tan}\mathrm{42}° \\ $$$${Height}\:{of}\:{tree}=\mathrm{6}×.\mathrm{9}=\mathrm{5}.\mathrm{4}{m}\left({Approx}\right) \\ $$
Commented by Rio Michael last updated on 01/Sep/18
$${thanks}\:{sir} \\ $$