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A-boy-ran-around-a-circular-part-of-radius-14m-in-15s-Calculate-the-average-velocity-and-the-average-speed-




Question Number 22112 by tawa tawa last updated on 11/Oct/17
A boy ran around a circular part of radius 14m in 15s. Calculate the   average velocity and the average speed.
$$\mathrm{A}\:\mathrm{boy}\:\mathrm{ran}\:\mathrm{around}\:\mathrm{a}\:\mathrm{circular}\:\mathrm{part}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{14m}\:\mathrm{in}\:\mathrm{15s}.\:\mathrm{Calculate}\:\mathrm{the}\: \\ $$$$\mathrm{average}\:\mathrm{velocity}\:\mathrm{and}\:\mathrm{the}\:\mathrm{average}\:\mathrm{speed}. \\ $$
Answered by $@ty@m last updated on 11/Oct/17
Average Verlocity=((Displacement)/(time))  =(0/(15))=0  Average Speed=((Distance)/(time))  =((2π.14)/(15))  =((2×22×2)/(15))  =((88)/(15))  =5.87 m/s
$${Average}\:{Verlocity}=\frac{{Displacement}}{{time}} \\ $$$$=\frac{\mathrm{0}}{\mathrm{15}}=\mathrm{0} \\ $$$${Average}\:{Speed}=\frac{{Distance}}{{time}} \\ $$$$=\frac{\mathrm{2}\pi.\mathrm{14}}{\mathrm{15}} \\ $$$$=\frac{\mathrm{2}×\mathrm{22}×\mathrm{2}}{\mathrm{15}} \\ $$$$=\frac{\mathrm{88}}{\mathrm{15}} \\ $$$$=\mathrm{5}.\mathrm{87}\:{m}/{s} \\ $$

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