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A-car-travelling-at-36-km-h-due-North-turns-West-in-5-seconds-and-maintains-the-same-speed-What-is-the-acceleration-of-the-car-




Question Number 14921 by Tinkutara last updated on 05/Jun/17
A car travelling at 36 km/h due North  turns West in 5 seconds and maintains  the same speed. What is the acceleration  of the car?
$$\mathrm{A}\:\mathrm{car}\:\mathrm{travelling}\:\mathrm{at}\:\mathrm{36}\:\mathrm{km}/\mathrm{h}\:\mathrm{due}\:\mathrm{North} \\ $$$$\mathrm{turns}\:\mathrm{West}\:\mathrm{in}\:\mathrm{5}\:\mathrm{seconds}\:\mathrm{and}\:\mathrm{maintains} \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{speed}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{car}? \\ $$
Commented by ajfour last updated on 05/Jun/17
south-west (along △v^�  )
$${south}-{west}\:\left({along}\:\bigtriangleup\bar {{v}}\:\right) \\ $$
Commented by Tinkutara last updated on 05/Jun/17
Thanks Sir! My small doubt cleared.
$$\mathrm{Thanks}\:\mathrm{Sir}!\:\mathrm{My}\:\mathrm{small}\:\mathrm{doubt}\:\mathrm{cleared}. \\ $$
Answered by ajfour last updated on 05/Jun/17
∣ a^� ∣=∣((△v^� )/(△t))∣  = ((10(√2))/5)= 2(√2) m/s .
$$\mid\:\bar {\boldsymbol{{a}}}\mid=\mid\frac{\bigtriangleup\bar {\boldsymbol{{v}}}}{\bigtriangleup{t}}\mid\:\:=\:\frac{\mathrm{10}\sqrt{\mathrm{2}}}{\mathrm{5}}=\:\mathrm{2}\sqrt{\mathrm{2}}\:{m}/{s}\:. \\ $$
Commented by Tinkutara last updated on 05/Jun/17
What will be the direction of this  acceleration?
$$\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{this} \\ $$$$\mathrm{acceleration}? \\ $$

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