A-chord-which-is-a-perpendicular-bisector-of-radius-of-length-18cm-in-a-circle-has-length-

Question Number 111734 by Aina Samuel Temidayo last updated on 04/Sep/20

A chord which is a perpendicular

bisector of radius of length 18 cm in a

circle, has length .

Answered by Rasheed.Sindhi last updated on 04/Sep/20

{(\frac{c}{2})}^{2} + {(\frac{r}{2})}^{2} = r^{2}

{(\frac{c}{2})}^{2} + 9^{2} = 18^{2}

\frac{c}{2} = \sqrt{324 - 81} = 9 \sqrt{3}

c = 18 \sqrt{3}

Commented by Aina Samuel Temidayo last updated on 04/Sep/20

Diagram please \overset{}{?}

Commented by prakash jain last updated on 05/Sep/20

Commented by Aina Samuel Temidayo last updated on 05/Sep/20

Please how do you know the chord is

also bisected ?

Commented by prakash jain last updated on 05/Sep/20

Radius is perpendicular to chord

and perpendicular radius always

bisects chord

Commented by Aina Samuel Temidayo last updated on 05/Sep/20

Ok . Thanks .

Commented by Rasheed.Sindhi last updated on 05/Sep/20

T h a n X p r a k a s h s i r f o r h e l p o f

a n i c e d i a g r a m e t c .