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A-circle-with-center-3-1-passes-through-the-point-3-1-Find-it-s-equation-

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Question Number 27579 by Mcfaithal last updated on 10/Jan/18
A circle with center (−3,1) passes through the point (3,1). Find it′s equation
Acirclewithcenter(−3,1)passesthroughthepoint(3,1).Findit′sequation
Answered by Joel578 last updated on 10/Jan/18
r = distance between (−3,1) and (3,1) = (√((3 + 3)^2 + (1 − 1)^2 )) = 6 (x − a)^2 + (y − b)^2 = r^2 (x + 3)^2 + (y − 1)^2 = 36 x^2 + y^2 + 6x − 2y − 26 = 0
r=distancebetween(−3,1)and(3,1)=(3+3)2+(1−1)2=6(x−a)2+(y−b)2=r2(x+3)2+(y−1)2=36x2+y2+6x−2y−26=0

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