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A-colony-of-bacteria-if-left-undisturbed-will-grow-at-a-rate-proportional-to-the-number-of-bacteria-P-present-at-time-t-However-a-toxic-substance-is-being-added-slowly-such-that-at-time-t-the-bacte




Question Number 63424 by Rio Michael last updated on 04/Jul/19
A colony of bacteria if left undisturbed will grow at a rate  proportional to the number of bacteria, P present at time,t.  However,a toxic substance is being added slowly such that  at time t, the bacteria also die at the rate μPt where μ is  a positive constant.  (a)  Show that at time t the rate of growth of the bacteria in  the colony is governed by the differential equation   (dP/dt)= (k−μt)p where k is apositive constant.  when t=0, (dP/dt)=2P and when t=1, (dP/dt)=((19)/(10))P  (b) show that                 (dP/dt)= (1/(10))(20−t)P.   Sir Forkum Michael.
Acolonyofbacteriaifleftundisturbedwillgrowatarateproportionaltothenumberofbacteria,Ppresentattime,t.However,atoxicsubstanceisbeingaddedslowlysuchthatattimet,thebacteriaalsodieattherateμPtwhereμisapositiveconstant.(a)ShowthatattimettherateofgrowthofthebacteriainthecolonyisgovernedbythedifferentialequationdPdt=(kμt)pwherekisapositiveconstant.whent=0,dPdt=2Pandwhent=1,dPdt=1910P(b)showthatdPdt=110(20t)P.SirForkumMichael.

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