Menu Close

a-convergent-geometric-sequence-with-first-term-a-is-such-that-the-sum-of-the-terms-after-the-n-th-term-is-three-times-the-n-th-term-find-the-common-ratio-and-show-that-its-sum-to-infinity-is-




Question Number 92820 by prince 5 last updated on 13/May/20
a convergent geometric sequence with  first term a is such that the sum of  the terms after the n^(th)  term is  three times the n^(th)  term, find the  common ratio and show that its   sum to infinity is 4a.
aconvergentgeometricsequencewithfirsttermaissuchthatthesumofthetermsafterthenthtermisthreetimesthenthterm,findthecommonratioandshowthatitssumtoinfinityis4a.
Answered by prakash jain last updated on 12/May/20
For a geometric seres   fisrt term a  common ratio r  n^(th)  term=ar^(n−1)   sum=(a/(1−r))   (∣r∣<1 for covergence)  sum after n^(th)  term is same as  geometric series with first term  as (n+1)th term and common ratio r.  ((ar^n )/(1−r))=3ar^(n−1)   (r/(1−r))=3⇒r=3−3r⇒r=(3/4)  Sum of series=(a/(1−r))=4a
Forageometricseresfisrttermacommonratiornthterm=arn1sum=a1r(r∣<1forcovergence)sumafternthtermissameasgeometricserieswithfirsttermas(n+1)thtermandcommonratior.arn1r=3arn1r1r=3r=33rr=34Sumofseries=a1r=4a

Leave a Reply

Your email address will not be published. Required fields are marked *