A-conveyor-belt-is-driven-at-velocity-v-by-a-motor-Sand-drops-vertically-on-to-the-belt-at-a-rate-of-mkg-s-What-is-the-additional-power-needed-to-keep-the-conveyor-belt-moving-at-a-steady-speed-when- Tinku Tara June 4, 2023 Mechanics 0 Comments FacebookTweetPin Question Number 49966 by Necxx last updated on 12/Dec/18 Aconveyorbeltisdrivenatvelocityvbyamotor.Sanddropsverticallyontothebeltatarateofmkg/s.Whatistheadditionalpowerneededtokeeptheconveyorbeltmovingatasteadyspeedwhenthesandstartstofallonit?a)12mvb)mvc)12mv2d)mv2 Commented by Necxx last updated on 12/Dec/18 pleasehelpsirs Answered by mr W last updated on 12/Dec/18 intimeΔtsandofmassmΔtdropsontothebeltandwillbemovedinhorizontaldirectionfromzerospeedtospeedv.theworkdonetothesandisW=12(mΔt)v2thepowerneededisP=WΔt=12mv2 Commented by Necxx last updated on 13/Dec/18 thanksboss Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-49964Next Next post: calculate-0-dx-x-2-i-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.