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A-disc-of-radius-r-suspended-from-a-point-lie-on-itself-Find-out-the-minimum-time-period-of-oscillation-of-the-disc-




Question Number 53151 by Necxx last updated on 18/Jan/19
A disc of radius r suspended from  a point lie on itself.Find out the  minimum time period of oscillation  of the disc.
Adiscofradiusrsuspendedfromapointlieonitself.Findouttheminimumtimeperiodofoscillationofthedisc.
Answered by mr W last updated on 18/Jan/19
i hope i understand your question correctly.  maximum time period:  I=((3Mr^2 )/2)  Iα=−Mgrsin θ≈−Mgrθ  ((3Mr^2 )/2)α=−Mgrθ  α=(d^2 θ/dt^2 )=−((2g)/(3r))θ  ω=(√((2g)/(3r)))  ⇒T=2π(√((3r)/(2g)))
ihopeiunderstandyourquestioncorrectly.maximumtimeperiod:I=3Mr22Iα=MgrsinθMgrθ3Mr22α=Mgrθα=d2θdt2=2g3rθω=2g3rT=2π3r2g
Commented by mr W last updated on 18/Jan/19
maybe you meant something different.
maybeyoumeantsomethingdifferent.
Commented by Necxx last updated on 18/Jan/19
thank you so much.Thats just how  the question was framed
thankyousomuch.Thatsjusthowthequestionwasframed
Commented by mr W last updated on 18/Jan/19
what′s the solution given?
whatsthesolutiongiven?

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