Question Number 192990 by otchereabdullai@gmail.com last updated on 01/Jun/23
$${A}\:{fair}\:{die}\:{is}\:{tossed}\:{four}\:{times}\:.{what} \\ $$$${is}\:{the}\:{probability}\:{of}\:{obtaining}\:{a}\: \\ $$$${prime}\:{each}\:{time} \\ $$
Answered by som(math1967) last updated on 01/Jun/23
$${total}\:{outcome}=\mathrm{6}^{\mathrm{4}} \\ $$$${prime}\:{numbers}=\left\{\mathrm{2},\mathrm{3},\mathrm{5}\right\} \\ $$$$\therefore\:{favourable}\:{outcome}=\mathrm{3}^{\mathrm{4}} \\ $$$$\:{probability}\:{a}\:{prime}\:{each}\:{time} \\ $$$$=\frac{\mathrm{3}^{\mathrm{4}} }{\mathrm{6}^{\mathrm{4}} }=\frac{\mathrm{1}}{\mathrm{16}} \\ $$
Commented by otchereabdullai@gmail.com last updated on 01/Jun/23
$${thank}\:{you}\:{sir}! \\ $$