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Question Number 27769 by tawa tawa last updated on 14/Jan/18

A glass bottle full of mercury has mass 500 g . On being heated through 35 ° C,

2 . 43 g of mercury are expelled . calculate the mass of mercury remaining in

the bottle (Cubic expansivity of mercury is 1.8 \times 10^{- 4} per K .

linear expansivity of glass is 8.0 \times 10^{- 6} per K .

Answered by mrW2 last updated on 15/Jan/18

V = v o l u m e o f m e r c u r y i n g l a s s b e f o r e h e a t i n g

Δ V = c h a n g e o f v o l u m e o f m e r c u r y d u e t o h e a t i n g

Δ V / V = (1.8 \times 10^{- 4} - 3 \times 8.0 \times 10^{- 6}) \times 35 = 0.00546

\frac{V}{Δ V} = \frac{1}{0.00546} = 183.15

M a s s o f m e r c u r y i n g l a s s b e f o r e h e a t i n g

M = 183.15 \times 2.43 = 445.05 g

M a s s o f m e r c u r y r e m a i n i n g i n g l a s s a f t e r h e a t i n g

M^{'} = 445.05 - 2.43 = 442.62 g

Commented by tawa tawa last updated on 15/Jan/18

God bless you sir .