A-Golfer-practising-on-a-range-with-an-accelerated-tree-4-9m-above-the-fairway-is-able-to-strike-a-ball-so-that-it-leaves-the-club-with-a-horizontal-velocity-of-20m-s-Assume-the-acceleration-due-to

FacebookTweetPin

Question Number 183039 by Mastermind last updated on 18/Dec/22

$$\mathrm{A}\mathrm{Golfer}\mathrm{practising}\mathrm{on}\mathrm{a}\mathrm{range}$$$$\mathrm{with}\mathrm{an}\mathrm{accelerated}\mathrm{tree}4.9\mathrm{m}\mathrm{above}$$$$\mathrm{the}\mathrm{fairway}\mathrm{is}\mathrm{able}\mathrm{to}\mathrm{strike}\mathrm{a}\mathrm{ball}$$$$\mathrm{so}\mathrm{that}\mathrm{it}\mathrm{leaves}\mathrm{the}\mathrm{club}\mathrm{with}\mathrm{a}$$$$\mathrm{horizontal}\mathrm{velocity}\mathrm{of}20\mathrm{m}/\mathrm{s}.$$$$(\mathrm{Assume}\mathrm{the}\mathrm{acceleration}\mathrm{due}\mathrm{to}$$$$\mathrm{gravity}\mathrm{is}9.8\mathrm{m}/{\mathrm{s}}^2\mathrm{and}\mathrm{the}\mathrm{effect}\mathrm{of}\mathrm{air}$$$$\mathrm{resistance}\mathrm{maybe}\mathrm{ignored}\mathrm{unless}$$$$\mathrm{othewise}\mathrm{stated}$$$$1)\mathrm{How}\mathrm{long}\mathrm{after}\mathrm{the}\mathrm{ball}\mathrm{leaves}\mathrm{the}$$$$\mathrm{club}\mathrm{will}\mathrm{it}\mathrm{land}\mathrm{on}\mathrm{the}\mathrm{fairway}?$$$$2)\mathrm{What}\mathrm{horizontal}\mathrm{distance}\mathrm{will}\mathrm{the}$$$$\mathrm{ball}\mathrm{travel}\mathrm{before}\mathrm{striking}\mathrm{the}\mathrm{fairway}?$$$$3)\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{acceleration}\mathrm{of}\mathrm{the}\mathrm{ball}$$$$0.5\mathrm{s}\mathrm{after}\mathrm{being}\mathrm{hit}?$$$$4)\mathrm{Calculate}\mathrm{the}\mathrm{speed}\mathrm{of}\mathrm{the}\mathrm{ball}$$$$0.8\mathrm{s}\mathrm{after}\mathrm{it}\mathrm{leaves}\mathrm{the}\mathrm{club}?$$$$$$$$$$$$\mathrm{M}.\mathrm{m}$$

Answered by mr W last updated on 19/Dec/22

$$1)$$$$4.9=\frac{9.8t^2}{2}\Rightarrow t=1s$$$$2)$$$$20\times 1=20m$$$$3)$$$$atanytime:a=9.8m/s^2$$$$4)$$$$v_h=20m/s$$$$v_v=9.8\times 0.8=7.84m/s$$$$v=\sqrt{{20}^2+7.{84}^2}\approx 21.5m/s$$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com

FacebookTweetPin