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Question Number 55482 by pooja24 last updated on 25/Feb/19
A group of n students are numbered  continously from first sdtudent as 1,2,3,......  If 1101 digits had to be used in all,what is the   number of students in the group
Agroupofnstudentsarenumberedcontinouslyfromfirstsdtudentas1,2,3,If1101digitshadtobeusedinall,whatisthenumberofstudentsinthegroup
Answered by mr W last updated on 25/Feb/19
1,2,3...,9⇒Σ=9×1=9 digits  10,11,12,...,99⇒Σ=90×2=180 digits  100,101,102,...,999⇒Σ=900×3=2700 digits  since totally 1101 digits are used,  n must be a 3−digit number  9+180+(n−99)×3=1101  ⇒n=403  i.e. there are 403 students in the group.
1,2,3,9Σ=9×1=9digits10,11,12,,99Σ=90×2=180digits100,101,102,,999Σ=900×3=2700digitssincetotally1101digitsareused,nmustbea3digitnumber9+180+(n99)×3=1101n=403i.e.thereare403studentsinthegroup.
Commented by tanmay.chaudhury50@gmail.com last updated on 25/Feb/19
excellent sir...
excellentsir
Commented by mr W last updated on 25/Feb/19
thanks sir!  if m=f(n) is the total number of digits  from 1 to n. is it possible to find a  formula for f(n) in terms of n?  furthermore find n=f^(−1) (m) if   possible.
thankssir!ifm=f(n)isthetotalnumberofdigitsfrom1ton.isitpossibletofindaformulaforf(n)intermsofn?furthermorefindn=f1(m)ifpossible.

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